IBM Aptitude interview Questions with answers

IBM Aptitude interview Questions

International Business Machines Corporation(IBM) is an American multinational technology company headquartered in Armonk, New York, with operations in over 170 countries

IBM conducts 3-4 rounds to select fresher as Software Developer in their organization.

• Aptitude test
• Technical interview
• HR interview

In this Post we’ll see the Aptitude interview questions asked at IBM

1) If 20 men can construct a divider of 112 meters in length in 6 days, what length of a comparable divider can be worked by 25 men in 3 days?

1. 69 meters.
2. 58 meters.
3. 70 meters.
4. 76 meters

Answer: 3. 70 Meters.

Solution:

20 men in 6 days can build 112 meters
25 men in 30 days can build=112*(25/20)*(3/6)
= 70 meters

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2) In a race of 600 meters, A can beat B by 60 meters and in a race of 500 meters; B can beat C by 50 meters. By what number of meters will A beat C in a race of 400 meters?

1. 76 meters.
2. 89 meters.
3. 71 meters.
4. 84 meters.

Answer: 1. 76 Meters

Solution:

Let’s assume A finishes the 600 m race in 60 sec, then
600/60 = 10 m/sec is his speed
B traveled (600-60 = 540 m in 60 sec, therefore
540/60 = 9 m/sec is B’s speed

“in a race of 500 metres, B can beat C by 50 metres.”
500/9 = 55.56 sec is B’s time to finish a 500 m race
C traveled 500-50 = 450 m in 55.56 sec, therefore
450/55.56 = 8.1 m/sec is C’s speed

By how many will A beat C in a race of 400 metres?
400/10 = 40 sec for A to run a 400 m race
C will travel 8.1*40 = 324 m in 40 sec therefore
C will be 400-324 = 76 m behind when A crosses the finish line

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3) On the off chance that the accumulated dividends on a specific total of cash for a long time at 10% for each annum be Rs. 993, what might be the basic intrigue?

1. Rs.840
2. Rs.590
3. Rs.695
4. Rs.900

Answer: 4. Rs. 900

Solution:

Let P = Principal
A – Amount
We have a = P (1 + R/100)3 and CI = A – P
ATQ 993 = P (1 + R/100)3 – P
P = Rs 3000/ –
Presently SI @ 10% on Rs 3000/ – for 3 yrs = (3000 x 10 x 3)/100
= Rs 900/ –

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4) What yearly portion will release an obligation of Rs. 4600 due in 4 years at 10% straightforward intrigue?

1. 1000
2. 1330
3. 1600
4. None of these

Answer: 1. 1000

Solution:

Give the yearly portion a chance to be Rs.100. The principal portion will be paid one year from now i.e. 3 years before it is in reality due. The second portion will be paid a long time from now i.e. 2 years before it is in reality due.
The third portion will be paid 1 year before it is in reality due.
The fourth portion will be paid on the day the sum is in reality due.
On the main portion, the intrigue will be paid for a long time, on the second for a long time, on the third for 1 year, on the fourth for multi-year. Altogether an enthusiasm for a long time will be paid (3 + 2 + 1 + 0) on Rs. 100 @ 10%. Intrigue = (100 × 6 × 10)/100 = Rs. 60 and the essential is Rs 100 × 4 = Rs 400. The aggregate credit that can be released is Rs. 400 + 60 = Rs. 460. Here the system of Chain Rule will be connected. I.e. for Rs. 460 the portion required is Rs. 100, for Rs. 4600 the portion required is 4600 × 100/460 = Rs. 1000.

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5) A number whose fifth part expanded by 5 is equivalent to its fourth part lessened by 5, is

1. 140.
2. 180.
3. 200.
4. 270

Answer: 3. 200.

Solution:

X/5 + 5 = x/4 – 5
⇒ x/5 – x/4 = 10
X/20 = 10
⇒ x = 200

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6) Two numbers are with the end goal that the proportion between them is 3:5, however in the event that each is expanded by 10, the proportion between them ends up 5:7. The numbers are

1. 7, 5
2. 7, 12
3. 13, 29
4. 15, 25

Answer: 4. 15, 25

Solution:

NO. Are in the ratio of 3:5
Let no be 3x and 5x
(3x+10): (5x+10) =5:7
X=5
NO are (15, 25)

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7) A man pushes downstream 30 km and upstream 18 km, taking 5 hours each time. What is the speed of the stream (current)?

1. 1.2 KM/HR
2. 1.7 KM/HR
3. 2.8 KM/HR
4. 4.8 KM/HR

Answer: 1. 1.2 KM/HR

Solution:

Let x=speed of boat and y=speed of current
=30/ (x+y)=18/(x-y)=5 by solving y=1.2 km/hr

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8) A train 125 meter long is running at 50 km/hr. In what time will it pass a man running at 5 km/hr in a similar bearing in which the train is going?

1. 15 sec
2. 10 sec
3. 60 sec
4. 55 sec

Answer: 2. 10 sec.

Solution:

Distance=125 meter speed=50-5=45km/hr=>45*5/18=12.5 m/s
Time=125/12.5=10sec

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9) A is twice as fast as B is thrice as fast as C. The journey covered by C in 42 minutes, what will be covered by A is

1. 21 MIN
2. 64 MIN
3. 17 MIN
4. 40 MIN

Answer: 3. 17 MIN.

Solution:

B is thrice as fast as C
C covered in 42 minutes
B covered in 42/3=14 min
A is twice as fast as B
A covers in 14*(1/2) = 7 min

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10) A can complete a work in 40 days and B in 28 days. In the event that A and B together take every necessary step, at that point roughly in how long will a similar function be finished?

1. 17 days
2. 14 days
3. 16 days
4. 29 days

Answer: 3. 16 days

Solution:

A’s 1day’s work = 1/40
B’s 1day’s work = 1/28
They can cooperate in = 1/40 + 1/28 = 16 days (estimate)

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11) Teena is more youthful than Rani by 6 years. On the off chance that the proportion of their ages is 6:8, discover the time of Teena:

1. 18 years
2. 16 years
3. 17 years
4. 19 years

Answer: 1. 18 years

Solution:

On the off chance that Rani Age is x, at that point Teena age is x-6,
So (x-6)/x = 6/8
=> 8x-48 = 6x
=> 2x = 48
=> x = 24
So, Teena age is 24-6 = 18 years

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12) A man purchases a book for Rs.29.50 and offers it for Rs 31.10. Discover his gain percent.

1. 8.1%
2. 5.4%
3. 9.8%
4. 2.4%

Answer: 2. 5.4%

Solution:

So we have C.P. = 29.50
S.P. = 31.10
Gain = 31.10 – 29.50 = Rs. 1.6
Gain %=( Gain/Cost*100)%
= (1.6/29.50*100)%=5.4%

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13) Think about the arrangement: 464, 232, 240, 120, ____, 64. What number should fill the clear?

1. 127
2. 128
3. 138
4. 126

Ans. 2. 128

Step-by-step explanation:

Given

Think about the arrangement: 464, 232, 240, 120, ____, 64. What number should fill the clear?

• First consider the numbers given in the series
•  464, 232, 240, 120,…. , 64
•  Consider the number 464. Divide by 2 we get 232
•  Add 8 to the given number, so it will be 232 + 8 = 240
• Again divide the number 240 / 2 we get 120
• Add 8 to the number, so 120 + 8 = 128
•  Again divide the number 128 / 2 we get 64
• So the process is first divide by 2  and add 8 to the number obtained.
• So the missing number is 128

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14) Look at the series: A4, __, C16, D32, E64. What number should fill the blank?

1. B16
2. D4
3. B8
4. B10

Answer: 3

Solution:

The letters Increase by 1; the numbers are duplicated by 2.

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15) A quick typist can type some issue in 2 hours and a moderate typist can type the same in 3 hours. In the event that both kinds consolidate, in what amount of time will they wrap up?

1. 2.12 hr
2. 1 .29 hr
3. 1.12 hr
4. 1.20 hr.

Answer: 3

Solution:

The quick typist’s work done in 1 hr = 1/2 The moderate typist’s work done in 1 hr = 1/3 If they work to join, work is done in 1 hr = 1/2+1/3 = 5/6 So, the work will be finished in 6/5 hours. i.e., 1+1/5 hours = 1hr 12 min

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16) Two trains running in inverse ways cross a man remaining on the stage in 27 seconds and 17 seconds separately and they cross each other in 23 seconds. The ratio of their speed is:

1. 2: 3
2. 3: 2
3. 3: 6
4. None of these