Numbers Aptitude Questions & Answers – Test Paper 2

Numbers Aptitude Questions & Answers with explanation – Test Paper 2

1) Which of the following numbers is divisible by 9?

1. 67578
2. 56785
3. 45678
4. 65889

The Correct answer is (4)

Answer with explanation:

A number is divisible by 9 if the sum of its digits is divisible by 9.

Sum of the digits of the given numbers are;

6+7+5+7+8= 33

5+6+7+8+5= 31

4+5+6+7+8= 30

6+5+8+8+9= 36

The sum of the digits of the number 65889 is 36 which is divisible by 9, so the correct answer is 65889.

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2) If (2^p + 1) is a prime number, which one of the following digits could be the value of p?

1. 3
2. 4
3. 5
4. 6

The Correct answer is (2)

Answer with explanation:

In such questions, each alternative should be tried.

So, if P = 3, we will get; 8 + 1= 9

If P = 4, we will get; 16 + 1 = 17

If P = 5, we will get; 32 + 1 = 33

If P= 6, we will get; 64 + 1= 65

Out of the four results, only 17 is the prime number. So, the required value of the P is 4.

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3) Find the number of three-digit numbers which are divisible by 6.

1. 150
2. 130
3. 120
4. 110

The Correct answer is (1)

Answer with explanation:

The required three digit numbers would be 102, 108, 114, 120…990 and 996.

The sequence of numbers shows that it is an arithmetic progression, where ‘a’ = 102, ‘d’ = 6 and last number = 996

Let the number of terms = n

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4) What is the sum of first 35 natural numbers?

1. 610
2. 630
3. 645
4. 660

The Correct answer is (2)

Answer with explanation:

First 35 natural numbers are 1, 2, 3, 4, 5…..35

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5) Given that 1+2+3+.. +9 = 45, find the value of (11+12+13+..+19).

1. 125
2. 130
3. 135
4. 140

The Correct answer is (3)

Answer with explanation:

11+12+13+…+19 is an arithmetic progression with number of terms ‘n’ = 9, first term = 11 and last term = 19.

Apply formula; Sn = n/2 (first term + last term)

Required value or sum = 9/2 ( 11 + 19)

= 4.5 * 30 = 135

 

Also Check the Test paper 3