**Numbers Aptitude Questions & Answers with explanation – Test Paper 2**

1) Which of the following numbers is divisible by 9?

- 67578
- 56785
- 45678
- 65889

The Correct answer is (4)

**Answer with explanation:**

A number is divisible by 9 if the sum of its digits is divisible by 9.

Sum of the digits of the given numbers are;

6+7+5+7+8= 33

5+6+7+8+5= 31

4+5+6+7+8= 30

6+5+8+8+9= 36

The sum of the digits of the number 65889 is 36 which is divisible by 9, so the correct answer is 65889.

2) If (2^{p} + 1) is a prime number, which one of the following digits could be the value of p?

- 3
- 4
- 5
- 6

The Correct answer is (2)

**Answer with explanation:**

In such questions, each alternative should be tried.

So, if P = 3, we will get; 8 + 1= 9

If P = 4, we will get; 16 + 1 = 17

If P = 5, we will get; 32 + 1 = 33

If P= 6, we will get; 64 + 1= 65

Out of the four results, only 17 is the prime number. So, the required value of the P is 4.

3) Find the number of three-digit numbers which are divisible by 6.

- 150
- 130
- 120
- 110

The Correct answer is (1)

**Answer with explanation:**

The required three digit numbers would be 102, 108, 114, 120…990 and 996.

The sequence of numbers shows that it is an arithmetic progression, where ‘a’ = 102, ‘d’ = 6 and last number = 996

Let the number of terms = n

4) What is the sum of first 35 natural numbers?

- 610
- 630
- 645
- 660

The Correct answer is (2)

**Answer with explanation:**

First 35 natural numbers are 1, 2, 3, 4, 5…..35

5) Given that 1+2+3+.. +9 = 45, find the value of (11+12+13+..+19).

- 125
- 130
- 135
- 140

The Correct answer is (3)

**Answer with explanation:**

11+12+13+…+19 is an arithmetic progression with number of terms ‘n’ = 9, first term = 11 and last term = 19.

Apply formula; Sn = n/2 (first term + last term)

Required value or sum = 9/2 ( 11 + 19)

= 4.5 * 30 = 135

Also Check the Test paper 3

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