**Numbers Aptitude Questions & Answers with explanation– Test Paper 6**

1) Find the value of √ (13√(13√(13√(13√(13√(13√(13))))))).

- √13
- 169
- (13)
^{(127/128)} - 2197

**Answer:** 3

**Explanation:**

When the process is not up to infinite, use this formula:

N ^{((2^t)-1 / 2^t)}, where the N is the digit, and t is the number of times the digit is repeated.

i.e., the number is 13, so we have: 13 ^{((2^7)-1 / 2^7)} =13^{(127/128)}

Hence, the required value is 13^{(127/128)}

2) Find the value of √ (248+ (√52+ (√144))).

- 4
- 8
- 12√2
- 16

**Answer:** 4

**Explanation:**

When the numbers are different, then we have to move from right to left direction.

i.e., √144=12, √ (52+12) => √64 = 8

√ (248+8) = √256 = 16

Hence, the required value is 16.

3) √ (1+ (27/169)) =1+x/13, find the value of x.

- 32
- 64
- 1
- 52

**Answer:** 3

**Explanation:**

√ (196/169) = 1+x/13

(14/13) -1 = x/13

1/13 =x/13

Hence, x=1

4) (1+1/2)(1+1/3)(1+1/4) ……. (1+1/x) = ?

- (x+2)/(x+1)
- (x+2)/(x+3)
- (x+1)/2
- (x+1)/3

**Answer:** 3

**Explanation:**

This type of questions can be solved by a short trick that is the last term numerator, and the first term denominator will be the answer.

i.e., 1+1/2 = 3/2, 1+1/3 = 4/3, 1+1/4 = 5/4, and so on.

(3/2)*(4/3)*(5/4) …. ((x+1)/x) = (½) (x+1)

The first term numerator cancelled by its next term denominator till the end.

In the end, we get (x+1)/2.

5) (1-1/2)(1-1/3)(1-1/4) ……. (1-1/x) = ?

- x
- x-1
- 1/ (x-1)
- 1/x

**Answer:** 4

**Explanation:**

This type of question can solve by a sort trick that is the first term numerator, and the last term denominator will be the answer.

i.e., 1-1/2 = 1/2, 1-1/3 = 2/3, 1-1/4 = 3/4 and so on

(1/2)*(2/3)*(3/4) …. ((x-1)/x) = (1) (1/x)

The first term denominator cancelled by its next term numerator till the end.

In the end, we get 1/x.

Also See Test Paper 7

[…] Also See the test Paper 6 […]